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  1. Can you give the IUPAC name for the following (CH_3)_3C-OH

    Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2 …

  2. What is the product of the following reaction? 1)CH_3 OH - Socratic

    Dec 23, 2017 · These are ostensibly acid-base reactions.... For ammonium we could write.... NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed ...

  3. Question #80fd6 - Socratic

    4.27 11.86 Ethanoic acid dissociates: sf (CH_3COOHrightleftharpoonsCH_3COO^ (-)+H^+) sf (K_a= ( [CH_3COO^-] [H^+])/ ( [CH_3COOH])=1.8xx10^ (-5)) These are equilibrium concentrations. To find …

  4. Question #ba7a1 - Socratic

    See explanation... Roughly speaking, we have the following facts: [H_3O^+] * [OH^-] = 10^(-14) pH = -log_10 [H_3O^+] pOH = -log_10 [OH^-] { (pH < 7 " acidic"), (pH ...

  5. Question #54b11 - Socratic

    The balanced equation is "CH"_3"CH"_2"COO"^"-" + "3S" + 4"OH"^"-" → "CH"_3"COO"^"-" + "HCO"_3^"-" + "3HS"^"-" + "H"_2"O" > The reaction is carried out at pH 8, so we must balance in …

  6. Question #c76b8 - Socratic

    Answer below Calcium oxide will dissolve to produce Calcium Hydroxide. It is as follows: CaO + H_2O to Ca (OH)_2 In essence: "base + water" to "alkali"

  7. Question #bb4d7 - Socratic

    Since there are both H^+ and OH^- ions in water, bicarbonate ions get hydrated really quickly to form carbonic acid, and the equation is HCO_3^ (-)+H^+rightleftharpoonsH_2CO_3 Know that, carbonic …

  8. Question #53967 - Socratic

    a. HI (aq) rarr H^ (+) + I^- b. HNO_3 (aq) rarr H^ (+) + NO_3^- c. Ba (OH)_2 (aq) rarr Ba^ (2+) + 2HO^-. "Hydrogen iodide" is in fact a very strong acid; as is "nitric acid", HNO_3 (in fact the former is a …

  9. Answers created by Paul - Socratic

    Q&A and Videos that make learning easy. Math, History, Chemistry, Algebra, Calculus, Biology and more.

  10. Question #6f366 - Socratic

    Here's what I get. > The reaction is a simple proton transfer from the acid to the amine to form an ammonium salt. The equation for the salt formation is underbrace ...